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Getting error
By Pp5344229@gmail.com, 3 months ago
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0
Getting error
Code:
num = int(input(f"Enter the Marks received: "))
percent = num/100
if percent>0.60:
for x in range(5):
print("salute")
print("\n")
else:
for x in range(5):
print("punishment")
print("\n")
Output:
Cell In [7], line 6
print("salute")
^
IndentationError: expected an indented block after 'for' statement on line 5
Error
If
Else
Conditional statements
Python
Indentationerror:
2 Answers
0
Hitendradixit18@gmail.com
Hit tab before print salute, and print punishment
0
Goutamp777
The error message is indicating that there is an indentation error on line 6, specifically that the print("salute") statement should be indented one more level to be inside the for loop on line 5.
The code should be:
num = int(input(f"Enter the Marks received: "))
percent = num/100
if percent>0.60:
for x in range(5):
print("salute")
print("\n")
else:
for x in range(5):
print("punishment")
print("\n")
This way, the print("salute") and print("\n") statements will be executed 5 times as the for loop iterates 5 times. If the percent is less than 0.60, it will print "punishment" 5 times.
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