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Jigisha Sata
2 years ago
import datetime
print('Today’s date and time is : ',
datetime.datetime.today())
date = datetime.date.today()
print(date)
print('Current Year :', date.year)
print ('Current Month :', date.month)
print ('Current Month Name:',date.strftime('%B'))
print ('Current Week Day :', date.day)
print ('Week Day Name :',date.strftime('%A'))
Today"s date and time is : 2021-07-07 09:37:26.512851
2021-07-07
Current Year : 2021
Current Month : 7
Current Month Name: July
Current Week Day : 7
Week Day Name : Wednesday
import datetime
d1 = datetime.date(2020,7,3) # First Date
print('Day 1 :', d1.ctime())
d2 = datetime.date(2019, 8, 18) # Second Date
print('Day 2 :', d2.ctime())
print('Number of Days:', d1-d2) # difference between the dates
today = datetime.date.today()
no_of_days = datetime.timedelta(days=3)
# Delta for Past Date
before_three_days = today - no_of_days
print('Before three Days:', before_three_days)
# Delta for future Date
after_three_days = today + no_of_days
print('After three Days:',after_three_days)
Day 1 : Fri Jul 3 00:00:00 2020
Day 2 : Sun Aug 18 00:00:00 2019
Number of Days: 320 days, 0:00:00
Before three Days: 2021-07-04
After three Days: 2021-07-10
import datetime
today = datetime.date.today()
print('Today is: ',today)
no_of_days = datetime.timedelta(days=3)
before_three_days = today - no_of_days
print('Before three Days:', before_three_days)
after_three_days = today + no_of_days
d1 = datetime.date(2019,5,5)
print( 'Date 1 :',d1)
if d1 == before_three_days :
print ('Same Dates')
if today > d1:
print ('Past Date')
if d1 < after_three_days:
print ('Future Date')
Today is: 2021-07-07
Before three Days: 2021-07-04
Date 1 : 2019-05-05
Past Date
Future Date